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[Other resource1js

Description: 一位计数器,按p3.2数码管加1,到9后回0,同时小喇叭响一下报警码管数据p0,数码管控制p2口,按键p3.2口 ,喇叭p3.3-a counter, according to p3.2 plus a digital pipe to the back nine after 0, Also horn ring for what police code of data p0, digital control p2 mouth, keypad p3.2 mouth, the loudspeaker p3.3
Platform: | Size: 1366 | Author: stone | Hits:

[Other resource1jb

Description: 8051单片机的一位计数器,按p3.2数码管加1,到9后回0,同时小喇叭响一下报警-8051 MCU a counter, according to p3.2 plus a digital pipe to the back nine after 0, Also horn ring for what Alarm
Platform: | Size: 1612 | Author: stone | Hits:

[Other resource6jisu

Description: 8051的6位计数器,按p3.2数码管加1,到9后回0,同时小喇叭响一下报警-8051 six counters, according to p3.2 plus a digital pipe to the back nine after 0, Also horn ring for what Alarm
Platform: | Size: 4398 | Author: stone | Hits:

[Communicationrecordid

Description: 当你的电话语音卡收不到主叫号码的时候,可以用这个程序来测试 步骤 1)选择好通道号 2)选择格式 3)选择开始 4)拨打电话 当程序接收不到主叫的时候,你可以把现场的主叫声音录下来进行分析 步骤 1)选好通道 2)选择录音 3)拨打电话 4)三声回铃声以后,选择停止录音,生成record.pcm主叫声音文件 5)用语音编辑工具打开record.pcm 6)对照网页http://www.dj.com.cn/support/cid/techid.asp的图形来进行分析-When your telephone can not receive Caller ID card, they can use this procedure to test the step 1) the choice of a good channel No. 2) Select the format 3) Select Start 4) When the procedure call when the caller can not receive, You can put the caller at the scene recorded sound analysis steps 1) select Channel 2) Select recording 3) call 4) Back to ring three times, the choice to stop recording, sound files generated record.pcm caller 5) voice editing tool to open record.pcm6) control of the graphics page to http://www.dj.com.cn/support/cid/techid.asp analysis
Platform: | Size: 487424 | Author: li | Hits:

[SCM1js

Description: 一位计数器,按p3.2数码管加1,到9后回0,同时小喇叭响一下报警码管数据p0,数码管控制p2口,按键p3.2口 ,喇叭p3.3-a counter, according to p3.2 plus a digital pipe to the back nine after 0, Also horn ring for what police code of data p0, digital control p2 mouth, keypad p3.2 mouth, the loudspeaker p3.3
Platform: | Size: 1024 | Author: stone | Hits:

[SCM1jb

Description: 8051单片机的一位计数器,按p3.2数码管加1,到9后回0,同时小喇叭响一下报警-8051 MCU a counter, according to p3.2 plus a digital pipe to the back nine after 0, Also horn ring for what Alarm
Platform: | Size: 1024 | Author: stone | Hits:

[SCM6jisu

Description: 8051的6位计数器,按p3.2数码管加1,到9后回0,同时小喇叭响一下报警-8051 six counters, according to p3.2 plus a digital pipe to the back nine after 0, Also horn ring for what Alarm
Platform: | Size: 4096 | Author: stone | Hits:

[OtherJosephProblem-C

Description: 用C语言解决约瑟夫环问题,约瑟夫环问题描述:设编号为1,2,…,n(n>0)个人按顺时针方向围坐一圈,每人持有一个正整数密码(可用随机数产生)。开始时任意给出一个报数上限值m,从第一个人开始顺时针方向自1起顺序报数,报到m时停止报数,报m的人出列,将他的密码作为新的m值,从他在顺时针方向上的下一个人起重新自1起顺序报数,报到新m值的人出列;如此下去,直到所有人全部出列为止。要求设计一个程序模拟此过程,并给出出列人的编号序列。 -Using C language to solve the issue of Joseph Ring, Joseph Ring Problem Description: Let numbered 1,2, ..., n (n> 0) individuals according to a clockwise direction around a circle, one person holding a positive integer password (available random number generated). The beginning of any given number of a reported upper limit of m, from the beginning of the first person clockwise order starting from 1 is reported the number of stops reported back m the number of people who reported that m out of his password as a new value m , from his in a clockwise direction on the next person since 1 have been re-reported the number of the order, appearance, the new m value of the listed persons it goes on like this until all the column until all. Asked to design a simulation of this process, procedures, and gives the number of people out of sequence.
Platform: | Size: 1024 | Author: eva yin | Hits:

[SCMMT8880Code

Description: DTMF双向收/发集成电路MT8880专门为双音频信号的收、发而设计,它既能产生发送双音频信号,又能对双音频信号进行接收译码,还能判断各种信号音(拨号音、回铃音、忙音)。以上就是它的应用电路和程序-Two-way DTMF collection/fat MT8880 IC specifically for the dual audio signals received, the design, it could have sent dual audio signal, while the dual audio signal decoding receiver, but also to judge the sound signal (dial tone , ring back tone, busy tone). Above is its application circuit and procedures
Platform: | Size: 54272 | Author: 徐徐 | Hits:

[DocumentsjosepRing

Description: joseph环。任务:编号是1,2,……,n的n个人按照顺时针方向围坐一圈,每个人只有一个密码(正整数)。一开始任选一个正整数作为报数上限值m,从第一个人开始顺时针方向自1开始顺序报数,报到m时停止报数。报m的人出列,将他的密码作为新的m值,从他在顺时针方向的下一个人开始重新从1开始报数,如此下去,直到所有人全部出列为止-joseph ring. Tasks: number is 1,2, ... ..., n of the n individuals in accordance with the clockwise direction around a circle, each person there is only one password (positive integer). One began to choose a positive integer as the number of reported upper limit m, from the first individual to start a clockwise direction since the beginning of the order of one off, back off m stop. Reported m the person out of his password as the new m value, in a clockwise direction from his next re-started from the beginning of one off, it goes on like this until all the column until all
Platform: | Size: 55296 | Author: zhang shun | Hits:

[OtherRing

Description: 电网规划中搜索环路的程序,通过给定的网络拓扑结构,判定该网络是否连通,如果连通,判定是否有回路,如果有回路,返回组成改回路的线路集合.-Search network planning process loop through a given network topology, determine whether the connectivity of the network, if connected, to determine whether there is any loop, if loop to loop back to the composition of a collection of lines.
Platform: | Size: 1024 | Author: 万振东 | Hits:

[Embeded-SCM Developqdq

Description: S0-S7为8路抢答按键输入,LD0-LD7为8路指示输出,抢答成功的路其相应的LD亮,平时为灭。接于INT0上的S8作为裁判、启动键。当按下此键后抢答才有效,否则视为违规,有效抢答响一长声,违规抢答响2短声。启动后LD按1秒速度流动闪亮30秒,每秒响一短嘀声。超过30秒未抢答作废:响四长声。有效抢答后对应的LD亮,LD停止流动。此时只有2个裁判健有效:按下ok-key为回答正确键,蜂鸣器响4声,按下cp-key为回答错误,蜂鸣器响3声。此时又回到初始状态,等待出题并按下cp-key开始抢答-S0-S7 for Answer 8 keystrokes, LD0-LD7 instructions for 8-way output, Answer successful implementation of the LD and the corresponding light, usually to eliminate. Then in the S8 as INT0 appear, start button. When pressing the Answer key to be valid, otherwise regarded as a violation, effective Answer a long ring sound, ring violation Answer 2 short sound. LD after 1 second the speed of the flow by 30 seconds flashes per second嘀sound a short ring. Answer not more than 30 seconds invalid: four long acoustic sound. Answer effective after the corresponding LD-liang, LD to stop the flow. At this point, only two appear effective Kin: ok-key by pressing the right button to answer, 4 ring buzzer sound, press the cp-key to answer the wrong buzzer sound ring 3. At this point back to the initial state, waiting for a title and press the start cp-key Answer
Platform: | Size: 3072 | Author: 王宇 | Hits:

[assembly language222221

Description: 下面的程序为读出RC500和MIFARE卡的序列号,选择一个卡,将该卡的20块初始化成值块且备份到21块最后使该卡进入HALT状态,且驱动2kHz蜂鸣器响200次。-The following procedure for reading out the RC500 and MIFARE card serial number, select a card, the card 20 is initialized as the value of block 21 and back up to the end of the card to enter the HALT state, and drive 200 ring buzzer 2kHz times.
Platform: | Size: 4096 | Author: 张斌 | Hits:

[Otherjh17

Description: 本文件夹包含的是针对电话交换系统的C51程序源代码,包含了电话串口之间的通信功能,以及控制回铃音的程序源代码-This folder contains the telephone exchange system for the C51 source code, including a telephone communication between the serial port, and control ring back tone of the program source code
Platform: | Size: 38912 | Author: rosabest | Hits:

[Embeded-SCM Developjishuqi

Description: daojishi.asm 倒计时器 开机默认为15秒,p32启动键,p34个位调整,p35十位调整 9999jishu.asm 6位数的计数器源程序,可以从0一直到999999,按p3.2计数,开机显示000000 9jishu.asm 一位计数器,按p3.2数码管加1,到9后回0 d9999.asm 可预制的倒计时钟,2位显示 p34个位调整p35十位调整 p32启动! 9keybb.asm 一位计数器,按p3.2数码管加1,到9后回0,同时小喇叭响一下报警,该程序是在一位计数器的基础上改进过来的 setkey.asm 可预制的倒计时钟,p35个位,p34十位,p32确定-daojishi.asm countdown 15 seconds by default boot device, p32 start button, p34 a bit to adjust, p35 10 adjustment 9999jishu.asm 6-digit counter source, you can have from 0 to 999999, according to p3.2 count, the boot Display 000000 9jishu.asm a counter, according to p3.2 digital channels with 1 to 9 after the return to 0 d9999.asm can pre-countdown clock, two showed p34-digit adjusted adjustment p32 p35 10 start! 9keybb.asm a counter, according to p3.2 digital channels with 1 to 9 back to 0 after the same time, what little horn ring alarm, the program is an improvement over the counter on the basis of the setkey.asm can be pre- countdown clock, p35 bits, p34 10, p32 OK
Platform: | Size: 12288 | Author: 马国娟 | Hits:

[Otherbell

Description: 电话用户信令控制器,此控制器完成一个电话接续过程中控制忙音,回铃音,振铃输出的功能-Phone users signaling controller, this controller to complete the process of controlling a telephone follow busy tone, ring back tone, ring out the functions
Platform: | Size: 1024 | Author: gab | Hits:

[Algorithmjosephringasmallprogramm

Description: 一个约瑟夫环小程序,练练手可以参照一下。任务:编号是1,2,……,n的n个人按照顺时针方向围坐一圈,每个人只有一个密码(正整数)。一开始任选一个正整数作为报数上限值m,从第一个仍开始顺时针方向自1开始顺序报数,报到m时停止报数。报m的人出列,将他的密码作为新的m值,从他在顺时针方向的下一个人开始重新从1报数,如此下去,直到所有人全部出列为止。设计一个程序来求出出列顺序。 -Joseph ring a small program and thought they could consult a hand. Task: number is 1,2, ... ..., n of the n individuals in accordance with the sitting clockwise circle, each person has only one password (positive integer). Choose a positive integer beginning, as the reported upper limit of the number of m, starting from the first is still the order of a clockwise direction starting from a report number, report the number of m, to stop reporting. Who reported m out of the column, his password as the new m value, in a clockwise direction from his next start back from a reported personal number, it goes on until everyone up all the columns. Design a program to calculate the column order.
Platform: | Size: 1024 | Author: hantanqingshi | Hits:

[matlabweiyingfangzhen

Description: 对CT图像进行radon变换以及IRADON反变换,并画出弦图,实现环形伪影的仿真-CT images of the radon transform and IRADON inverse transform, and draw the chord diagram to realize the simulation of ring artifacts
Platform: | Size: 1024 | Author: 戚曼曼 | Hits:

[Other GamesNine-serial-programming-solution1

Description: 九连环的每个环互相制约,只有第一环能够自由上下。要想下/上第n个环,就必须满足两个条件,第一个环除外。一、第n-1个环在架上;二、第n-1个环前面的环全部不在架上。玩九连环就是要努力满足上面的两个条件。解下九连环本质上要从后面的环开始下,而先下前面的环,是为了下后面的环,前面的环还要装上,不算是真正地取下来-Nine chain of each ring and check each other freely up and down only the first ring. To the next/first n rings, two conditions must be met, except for the first ring. I, n-1 rings on the shelf II, n-1 rings ring in front of all the outside rack. Play nine chain is to strive to meet the above two conditions. Nine off his chain is essentially starting from the back under the ring, and the first under the front of the ring, next to the back of the ring, but also fitted with the ring in front, is not really taken off
Platform: | Size: 10240 | Author: hutua | Hits:

[Windows DevelopMMT88800T

Description: MT8880产生发送和接收译码各使用了一片集成电路,而DTMF双向收/发集成电路MT8880专门为双音频信号的收、发而设计,,它既能产生发送双音频信号,又能对双音频信号进行接收译码,还能判断各种信号音(拨号音、回铃音、忙音)。-good 已通过测试。 -MT8880 generate send and receive decoding the use of an integrated circuit, DTMF bi-directional transmit/receive IC MT8880 specifically for the dual audio signal of closing, hair design, it not only generated to send the audio signal, but also two-tone The signal receiving decoder can also determine a variety of tones (dial tone, ring back tone, busy tone).-Good has been tested.
Platform: | Size: 104448 | Author: zcl1233 | Hits:
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